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Sep 28, 2018 · 1. What do you mean by call the variable ? · that returns the location of the url...try it in your browser you should get the url to this page.
Feb 7, 2017 · if(inputUrl.toLowerCase().indexOf("stackoverflow.com") > -1) { ... }.
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Oct 26, 2013 · Ask questions, find answers and collaborate at work with Stack Overflow ... I have some problems to put a URL-function within an if-statement ...
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Mar 3, 2021 · You cannot use "is" with a literal; if x is 'yes': throws the the SyntaxError. You have to use if x == 'yes': instead.
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