... 9 + 16 = 25 = 25 = 25 ( True ) : .x must be 16 here . 243 3x3x3x3x3 X = 5 5 16807 7 X7 X7 X7 X7 3 = > X =7 7. ( C ) ... 10 of - 5 = 3x2 : 3 of 2x3-5 + 5x5-5x5–5 : 10 x 5 = 3x2 = 3 of 2 x3 = ( 5 + 5x 5 : 25-5-2 ) 1 3x2 = 3 of 2 x3 ...

... 10 is (1) 1 (2) 2 (3) 5 (4) 100 (5) 105 2. The cube of 9 is 7. Find = 503 to the nearest tenth. (1) 22.4 (2) 22.5 (3) ... square root of 1175, to the near- est whole number, is (1) 32 (2) 33 (3) 34 (4) 35 (5) 36 www.petersons.com (1) ...

... 5 6 Morn . 7 3 2 32 15 13 24.0 23.3 735 821 12 59 22 7 12 51 10 5 29 037 757 3 4 11 40 25.0 35.5 9 22 955 13 319 8 12 54 50 5 52 1 53 849 322 7 26 26.0 47.7 10 32 11 18 13 715 9 12 58 30 615 38 9 40 358 2 49 N 27-0 59.9 11 41 13 11 12 10 13 ...

... square root of the product of the numbers . Example . - Find the simplest radical form and also the decimal value to three places of 2√3 × 5√2 . Solution . — 1 . 2 . 2√3 X 5√2 = 10√3.2 = 10√6 . 10√6 = 10 X 2.449 = 24.49 . When ...

... 3. = a3 + 3a2b + 3ab 2 + b 3 857 Example 9. Find the square root of 52 2116 Solution: We have, 52 2116 857 = 110889 ... 5 3 729 = 9 3 8 = 2 3 216 = 6 3 1000 = 10 3 27 = 3 3343 = 7 Example 10. What is the cube root of 125? Solution ...

Jens M. Melenk. 12ε 4ε 1 10-3 6 elements ; eps = 10 ^ ( - 3 ) ; both middle lines slightly skewed 10-4 10-5 10-6 b = 0.5 b = 0.25 Rel . Error in Energy -7 107 10-8 10-9 10ε 10-10 σε 10 0-11 ייייייייייייייייייייייייייייייייייייייייייי -12 b ...

... 10 15 ii. 2 √ 114 iii. 187 d. No. The correct answer is √ b+a = √ c. 1. Square 1 2 3 4 Side length (cm) 2 4 6 8 ... square root of that number. 10. The√ 2 times squares the in perimeter the first diagram of each corresponding ...

... 5 1.94498141 1.94602817 1.94589653 1.94591264 6 1.94571873 1.94593035 1.94590818 1.94591045 7 8 1.94590209 1.94591078 1.94587082 1.94591370 1.94590985 1.94591019 1.94591010 1.94591015 9 1.94590850 1.94591026 1.94591014 10 ... 3 -4 10 4.3 ...

... X10-7C 3 r = 5cm = 5 × 10-2m = 92 2 2C U 2 U2 − U1 = – Ս . U1 - 2 - 2 2 ... ( 1 ) 91 U2 - U1 U1 - = 21 % = 21 100 = 0.21 m = 6gm = 6x10-3kg As F = mg 1 9192 4πε 。 r2 = mg 9 × 10 ° ×× 10 3 1 10-72 = 6 × 10 - 3 × 9.8 ( 5 × 10-2 ) 2 ...

... ( 5 , 101 ) X U = SQRT ( X ) WRITE ( 6,202 ) X.U STOP 101 FORMAT ( F 10.3 ) 202 FORMAT ( ' _ SQRT ( ' , F 10.3 . ' ) = ' , F 10.3 ) END 10 _ { null line } : After inserting 9 ... 3 : : 5 6 : : 8 $ run for tranvs spunch = -obj READ ( 5 , 101 ) ...